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The reaction Ararr B follows first order...

The reaction `Ararr B` follows first order kinetics. The time taken for `0.8 mol` of `A` to produce `0.6 mol` of `B` is `1 hr`. What is the time taken for the conversion of `9.0 mol` of `A` to Product `0.675 mol` of `B` ?

A

1 hour

B

0.5 hour

C

0.25 hour

D

2 hours

Text Solution

Verified by Experts

The correct Answer is:
A
`A rarr B`
t = 0 0.8 0.6 + 0.6 mol
= 0.2 mol
Two half life's are involved in `0.8" mol "rarr 0.2" mol"`
In second case, `[A]_(t)=0.9-0.67=0.23" mol"`.
`0.9" mol"rarr 0.48" mol "rarr ~~ 0.23" mol"`
Again two half life's involve, so time taken to produce 0.67 mole B from 0.9 mol A is
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