The half-life of a reaction is halved as...

The half-life of a reaction is halved as the initial concentration of the reaction is doubled. The order of the reaction is

A

0.5

B

1

C

2

D

0

Verified by Experts

The correct Answer is:

C

For `II^(nd)` order reaction `t_(1//2)=(1)/(kC_(A_(0))) & (t_(1//2))=(1)/(2kC_(A_(0)))=(t_(1//2))/(2)`

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