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The rate constant of a reaction at tempe...

The rate constant of a reaction at temperature 200 K is 10 times less than the rate constant at 400 K. What is the activation energy `(E_(a))` of the reaction ? (R = gas constant)

A

1842.4 R

B

921.2R

C

460.6 R

D

230.3 R

Text Solution

Verified by Experts

The correct Answer is:
B
`log""(k_(2))/(k_(1))=(E_(a))/(2.303 R) ((1)/(T_(1))-(1)/(T_(2)))`
`log""(k_(2))/(k_(2)//10)=(E_(a))/(2.303 R)((1)/(200)-(1)/(400))`
log `10=(200 E_(a))/(2.303xxx200xx400 R)rArr E_(a) =230.3 xx 4R rArr E_(a) =921.2 R`
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