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In the reaction 3Ararr2B, rate of reacti...

In the reaction `3Ararr2B`, rate of reaction `+(d[B])/(dt)` is equal to :

A

`-(1)/(3) (d[A])/(dt)`

B

`-(2)/(3) ([A])/(dt)`

C

`+(2d[A])/(dt)`

D

`-(3)/(2) (d[A])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
B
For `3A rarr 2B`
`-(1)/(3) (d[A])/(dt) =(1)/(2) (d[B])/(dt)`
`(d[B])/(dt) =(2)/(3) ((-d[A])/(dt))`
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