For a reaction of reversible nature, net...

For a reaction of reversible nature, net rate is `((dx)/(dt))=k_(1)[A][B]-k_(2)[C]` hence, given reaction is :

A

B

C

D

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The correct Answer is:

B

`r_(f) =k_(1) [A][B] rArr r_(b)=k_(2) [C]" Net rate "=k_(1)[A] [B] -k_(2) [C]`

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