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For the following reaction, A overset(...

For the following reaction,
`A overset(500 K)rarr` Products
`A overset(400K//"catalyst")rarr` Product
If `((-d[A])/(dt))_(500 K)=-((d[A])/(dt))_(400 K)`
no catalyst in presence of catalyst Then `E_(a)` is approximately :

A

`200" kJ mol"^(-1)`

B

`100" kJ mol"^(-1)`

C

`20" kJ mol"^(-1)`

D

`120" kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`k_(500) =Ae^(-E_(a)//500R), k_(400) =Ae^(-(in_(a)-20)//400 R)`
Since `k_(500)=k_(400) (because (d[A])/(dt)|_(500k)=(d[A])/(dt) |_(400 k))`
`therefore e^(-E_(a)//500 R) =e^(-(E_(a)-20)//400 R) rArr (Ea)/(500 R) =(E_(a) -20)/(400 R)`
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