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Following reaction can take place in bot...

Following reaction can take place in both direction `A {:(k_(1)),(k_(2)):}B.` For the forward reaction and for the backward direction
`{:([B],"Rate"),(0.01M, 1xx10^(-2) Ms^(-1)),(0.02M, 2xx10^(-2) Ms^(-1)):}`
Hence, net reaction rate is :

A

`=k_(1) [A]-k_(2)[B]`

B

`=k_(1)-k_(2)[B]`

C

`=k_(1)[A]-k_(2)`

D

`=k_(1)-k_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Based on (A), rate is independent of (A) and when (B) is doubled, rate is also doubled.
Thus, for forward reaction rate law `=k_(1) [A]^(o) =k_(1)` and for backward reaction are law `=k_(2) [B]`
Thus, net rate `=k_(1) -k_(2) [B]`
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