The half-life period of a first-order chemical reaction is `6.93 min`. The time required for the completion of `99%` of the chemical reaction will be `(log 2 = 0.301)`

Options

A. 230.3 minutes
B. 23.03 minutes
C. 46.06 minutes
D. 460.6 minutes

Answer

C

Explanation

`[A_(o)])` initial concentration (amount)
[A] = final concentration (amount)
`therefore " "t=(2.303xx6.93)/(0.6932) log""(100)/(1) =46.06` minutes.