Home
Class 12
CHEMISTRY
For the equilibrium, A(g) rarr B(g) , ...

For the equilibrium,
`A(g) rarr B(g) , DeltaH` is -40 KJ/mol.
If the ratio of the activation energies of the forward `(E_(f))` and reverse `(E_(b))` reactions is `(2)/(3)` then:

A

`E_(f) =60" kJ/mol, "E_(b) =100" kJ/mol"`

B

`E_(f)=30" kJ/mol, "E_(b) =70" kJ/mol"`

C

`E_(f)=80" kJ/mol, "E_(b) =120" kJ/mol"`

D

`E_(f)=70" kJ/mol", E_(b) =30" kJ/mol"`

Text Solution

Verified by Experts

The correct Answer is:
C
`(E_(f))/(E_(b)) =(80)/(120) =(2)/(3)`
Promotional Banner

Similar Questions

Explore conceptually related problems

For the equilibrium, A(g)hArrB(g),DeltaH is -40kJ//mol , if the ratio of the activation energies of the forward (E_(f)) and reverse (E_(b)) reactions is 2/3, then

A+B rarr C, DeltaH = +60 kJ/mol E_(a_f) is 150 kJ. What is the activation energy for the backward reaction ?

For A+B rarr C+D, DeltaH=-20 kJ mol^(-1) , the activation energy of the forward reaction is 85 kJ mol^(-1) . The activation energy for backward reaction is …… kJ mol^(-1) .

For A + B to C + D, DeltaH = -20 kJ "mole"^(-1) . The activation energy for the forward reaction is 85 kJ. Then the activation energy for the backward reaction is ___

2NO(g) +Cl_(2)(g) rarr 2NOCl, DeltaH=-38 KJ If the activation energy for the forward reaction is 62 KJ , what is the activation energy for the reverse reaction?

In an exothermic reaction A rarr B , the activation energy of the forward reaction is 200 kJ mol^(-1) . The enthalpy of the reaction is 280 kJ mol^(-1) . The activation energy of the reverse reaction B rarr A is