A + 2B rarr C, the rate equation for thi...

A + 2B `rarr C, the rate equation for this reaction is given as
Rate = k[A] [B].
If the concentration of A is kept the same but that of B is doubled what will happen to the rate itelf?

A

halved

B

the same

C

doubled

D

quadrupled

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The correct Answer is:

C

`("Rate"_(1))/("Rate"_(2))=(k[A][B])/(k[A] 2[B]) =2" Rate"_(1) =" Rate"_(2)`
So, rate get doubled

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