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NO(2) required for a reaction is produce...

`NO_(2)` required for a reaction is produced by the decomposition of `N_(2)O_(5)` is `"CC"l_(4)` as per the equatiion `2N_(2)O_(5)(g)to4NO_(2)(g)+O_(2)(g)`. The initial concentration fo `N_(2)O_(5)` is `3.00 "mol"L^(-1)` and it is `2.75 "mol"L^(-1)` after 30 minutes. The rate of formation of `NO_(2)` is `4.67xx10^(-x) "mol" L^(-1)"min"^(-1)`. the numerical value of x is __________.

A

`2.083xx10^(-3)" mol L"^(-1)" m in"^(-1)`

B

`4.167xx10^(-3)" mol L"^(-1)" m in"^(-1)`

C

`1.667xx10^(-2)" mol L"^(-1)" m in"^(-1)`

D

`8.33xx10^(-3)" mol L"^(-1)" m in"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Rate of disappearance of `N_(2)O_(5) =((3-2.75))/(30) =(25)/(30) xx10^(-2)" M m in"^(-1)= ((5)/(6))xx10^(-2)" M m in"^(-1)`
Rate of formation of `NO_(2)=2` (rate of disappearance of `N_(2)O_(5))=(10)/(6)xx10^(-2)=1.667xx10^(-2)" M m in"^(-1)`
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