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The following statement(s) is (are) corr...

The following statement(s) is (are) correct:

A

A plot of log `k_(p)` versus 1/T is linear

B

A plot of log [X] versus time is linear for a first-order reaction, `X rarr P`

C

A plot of P versus 1/T is linear at constant volume

D

A plot of P versus 1/V is linear at constant

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statements are correct regarding chemical kinetics, we will analyze each statement step by step. ### Step 1: Analyze the first statement **Statement:** A plot of log Kp versus 1/T is linear. **Explanation:** The relationship between the equilibrium constant (Kp) and temperature (T) can be described by the van 't Hoff equation: \[ \ln K_p = -\frac{\Delta H}{R} \cdot \frac{1}{T} + C \] When we take the logarithm (base 10) of Kp, we can express it as: \[ \log K_p = -\frac{\Delta H}{2.303R} \cdot \frac{1}{T} + \text{constant} \] This equation is in the form of \( y = mx + c \), where \( y = \log K_p \), \( x = \frac{1}{T} \), and the slope \( m = -\frac{\Delta H}{2.303R} \). Thus, the plot of log Kp versus 1/T is indeed linear. **Conclusion:** This statement is correct. ### Step 2: Analyze the second statement **Statement:** A plot of log x versus time is linear for the first-order reaction x → p. **Explanation:** For a first-order reaction, the integrated rate law is given by: \[ \ln [A] = \ln [A_0] - kt \] Where [A] is the concentration of reactant A at time t, and k is the rate constant. If we convert this to log base 10: \[ \log [A] = \log [A_0] - \frac{k}{2.303} t \] This is also in the form of \( y = mx + c \) where \( y = \log [A] \), \( x = t \), and the slope \( m = -\frac{k}{2.303} \). Therefore, the plot of log x versus time is linear. **Conclusion:** This statement is correct. ### Step 3: Analyze the third statement **Statement:** A plot of P versus 1/T is linear at constant volume. **Explanation:** According to Gay-Lussac's law, for a fixed amount of gas at constant volume, pressure (P) is directly proportional to temperature (T): \[ P \propto T \] This can be expressed as: \[ P = kT \] If we rearrange this to express P in terms of 1/T, we get: \[ P = k \cdot T \] This does not yield a linear relationship when plotted against \( \frac{1}{T} \); instead, it results in a hyperbolic curve, not a straight line. **Conclusion:** This statement is incorrect. ### Step 4: Analyze the fourth statement **Statement:** A plot of P versus 1/V is linear at constant temperature. **Explanation:** According to Boyle's law, for a fixed amount of gas at constant temperature, pressure (P) is inversely proportional to volume (V): \[ P \propto \frac{1}{V} \] This can be expressed as: \[ P = k \cdot \frac{1}{V} \] This is indeed a linear relationship, where if we plot P against \( \frac{1}{V} \), we will get a straight line. **Conclusion:** This statement is correct. ### Final Answer: The correct statements are: 1. A plot of log Kp versus 1/T is linear. 2. A plot of log x versus time is linear for the first-order reaction x → p. 4. A plot of P versus 1/V is linear at constant temperature. ### Summary of Correct Statements: - **Correct Statements:** 1, 2, and 4.

To determine which statements are correct regarding chemical kinetics, we will analyze each statement step by step. ### Step 1: Analyze the first statement **Statement:** A plot of log Kp versus 1/T is linear. **Explanation:** The relationship between the equilibrium constant (Kp) and temperature (T) can be described by the van 't Hoff equation: \[ \ln K_p = -\frac{\Delta H}{R} \cdot \frac{1}{T} + C \] ...
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