The rate constant for the reaction
`2N_(2)O_(5) rarr 4NO_(2)+O_(2)`
is `3.0 xx 10^(-5) s^(-1)`. If the rate is `2.40 xx 10^(-5) mol L^(-1) s^(-1)`, then the concentration of `N_(2)O_(5)` (in `mol L^(-1)`) is

Options

A. `1.4`
B. `1.2`
C. `0.04`
D. 3

Answer

D

Explanation

As per units of rate constant, it follows first order kinetics w.r.t. `N_(2)O_(5)`
`[N_(2)O_(5)]=("rate")/(k) =(3.90xx10^(-5))/(1.3xx10^(-5))/(1.3xx10^(-5))=3M`