A solution of `Ni(NO_(3))_(2)` is electrolyzed between platium electrodes using a current of `5A` for `20 mi n`. What mass of `Ni` is deposited at the cathode ?

Explanation

Given current I = 5 A, `t = 20 xx60 s`, w= ?
`Q=Ixxt= 5xx20xx60 = 6000c`
Reaction for deposition Of Ni,
`Ni^(2+) + 2e^(-)`
`2 mol`
`2xx96500C` `rightarrow` Ni
1mol
` 58.7g`
Thus , `2xx96500 C` of electricity produces 58.7g Ni
`therefore 6000 C` of electricity would produce