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Which will reduce zinc oxide to zinc?...

Which will reduce zinc oxide to zinc?

A

Mg

B

Pb

C

CU

D

Fe

Text Solution

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The correct Answer is:
To determine which substance can reduce zinc oxide (ZnO) to zinc (Zn), we need to analyze the reduction potentials of the given substances: magnesium (Mg), lead (Pb), copper (Cu), and iron (Fe). The strongest reducing agent will be the one with the most negative reduction potential, as it can donate electrons more readily. ### Step-by-Step Solution: 1. **Identify the Reduction Reaction**: The reduction of zinc oxide can be represented as: \[ \text{ZnO} + 2e^- \rightarrow \text{Zn} + \text{O}^{2-} \] This shows that zinc oxide is being reduced to zinc by gaining electrons. 2. **Check the Standard Reduction Potentials**: The standard reduction potentials (E°) for the relevant half-reactions are: - For Zn²⁺ + 2e⁻ → Zn: E° = -0.76 V - For Mg²⁺ + 2e⁻ → Mg: E° = -2.37 V - For Pb²⁺ + 2e⁻ → Pb: E° = -0.13 V - For Cu²⁺ + 2e⁻ → Cu: E° = +0.34 V - For Fe²⁺ + 2e⁻ → Fe: E° = -0.44 V 3. **Determine the Strongest Reducing Agent**: The strongest reducing agent will be the one with the most negative E° value, as it can reduce other species more effectively. In this case: - Mg has the most negative potential (-2.37 V), making it the strongest reducing agent among the options. 4. **Conclusion**: Since magnesium has the lowest (most negative) reduction potential, it can effectively reduce zinc oxide to zinc. Therefore, the answer to the question is: \[ \text{Mg (Magnesium)} \] ### Final Answer: **Magnesium (Mg) will reduce zinc oxide to zinc.** ---

To determine which substance can reduce zinc oxide (ZnO) to zinc (Zn), we need to analyze the reduction potentials of the given substances: magnesium (Mg), lead (Pb), copper (Cu), and iron (Fe). The strongest reducing agent will be the one with the most negative reduction potential, as it can donate electrons more readily. ### Step-by-Step Solution: 1. **Identify the Reduction Reaction**: The reduction of zinc oxide can be represented as: \[ \text{ZnO} + 2e^- \rightarrow \text{Zn} + \text{O}^{2-} ...
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