Home
Class 12
CHEMISTRY
The amount of substance deposited by the...

The amount of substance deposited by the passage of 1 A of current for 1s is equal to :

A

Equivalent mass

B

Molecular mass

C

Electrochemical equivalent

D

Specific equivalent

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the amount of substance deposited by the passage of 1 A of current for 1 second, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Concept**: The amount of substance deposited during electrolysis is related to the charge passed through the electrolyte. This relationship is defined by Faraday's laws of electrolysis. 2. **Using the Formula**: The amount of charge (Q) passed is given by the formula: \[ Q = I \times T \] where: - \( Q \) = charge in coulombs - \( I \) = current in amperes (A) - \( T \) = time in seconds (s) 3. **Substituting Values**: In this case, we have: - \( I = 1 \) A - \( T = 1 \) s Therefore, substituting these values into the formula gives: \[ Q = 1 \, \text{A} \times 1 \, \text{s} = 1 \, \text{C} \] 4. **Relating Charge to Mass**: The mass of the substance deposited (m) can be calculated using the electrochemical equivalent (Z) of the substance: \[ m = Z \times Q \] Since we have determined \( Q = 1 \, \text{C} \), we can say: \[ m = Z \times 1 \, \text{C} = Z \] 5. **Conclusion**: The amount of substance deposited by the passage of 1 A of current for 1 s is equal to the electrochemical equivalent (Z) of the substance. ### Final Answer: The amount of substance deposited is equal to the electrochemical equivalent (Z).

To solve the question regarding the amount of substance deposited by the passage of 1 A of current for 1 second, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Concept**: The amount of substance deposited during electrolysis is related to the charge passed through the electrolyte. This relationship is defined by Faraday's laws of electrolysis. 2. **Using the Formula**: The amount of charge (Q) passed is given by the formula: \[ ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Mass of copper deposited by the passage of 2 A of current for 965 s through a 2 M solution of CuSO_(4) is (At. Mass of Cu= 63.5) __________.

The amount of energy expended during the passage of 1 ampere current for 100 sec under a potential of 115 V :

The ECE of metal is z the mass of metal deposited by the passage of 500 mA current through the solution for four minutes will be

The amount of silver deposited by passing 241. 25 C of current through silver nitrated solution is .

The amount of substance liberated when 1 ampere of current is passed for 1 second through an electrolytic solution is called ………………… .

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-