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If 3F of electricity is passed through t...

If `3F` of electricity is passed through the solutions of `AgNO_3, CuSO_4` and `AuCL_3`, the molar ration of the cations deposited at the cathode is .

A

1:1:1

B

1:2:3

C

3:2:1

D

`(6:3:2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`3Ag^(+) + 3e^(-)rightarrow 3Ag ,(3)/(2) Cu^(2+) + (3)/(2)xx2e^(-) to (3)/(2) Cu`
`Au^(3+) + 3e^(-)rightarrow Au`, Thus ratio of mol of `Ag: Cu: Au= 3: (3)/(2) : 1= 6:3:2`
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