Home
Class 12
CHEMISTRY
Resistance of 0.2 M solution of an elect...

Resistance of `0.2 M` solution of an electrolyte is `50 Omega`. The specific conductance of the solution is ` 1.3 S m^(-1)`. If resistance of the `0.4 M` solution of the same electrolyte is `260 Omega`, its molar conductivity is .

A

`(6250Sm^(2)mol^(-1))`

B

`6.25xx10^(-4)sm^(2)mol^(-1))`

C

`(625xx10^(-4) sm^(2) mol^(-1))`

D

`(62.5sm^(2)mol^(-1))`

Text Solution

Verified by Experts

The correct Answer is:
B
For 0.2M solution : `R = 50Omega`,G=(1)/(50)S`, `K=GxxG^(**)`
`therefore G^(ast)= (K)/(G) = 1.3 xx50m^(-1) = 65m^(-1)`
For 0.4M solution : `R = 260Omega ,G+(1)/(260), K = GxxG^(**) = (65)/(260)`
`therefore wedge_(m) = (K)/(1000C)= (0.25)/(1000xx0.4)= 6.25xx10^(-4)sm^(2) mol ^(-1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Resistance of 0.2 M solution of an electrolyte is 50Omega . The specific conductance of the solution is 1.4 Sm^(-1) . The resistance of 0.5 M solution of the same electrolyte is :

Resistance of 0.2 M solution of an electrolue is 50 Omega . The specific conductance of the solution is 1.4 S m^^(-1) . The resistance of 0.5 M solution of the same electrolyte is 280. Omega . The molar conducitivity of 0.5 M solution of the electrolyte is S m^2 "mol"^(-1) is.

The resistance of 0.01N solution of an electrolyte AB at 328K is 100ohm. The specific conductance of solution is cell constant = 1cm^(-1)

Resistance of a conductvity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 Omega . The conductivity of this solution is 1.29 Sm^(-1) . Resistance of the same cell when filled with 0.02M of the same solution is 520 Omega . the molar conductivity of 0.02M solution of the electrolyte will be: