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The values of wedge(m)^(oo) forNH(4)Cl,N...

The values of `wedge_(m)^(oo)` for`NH_(4)Cl,NaOH,` and `NaCl` are, respectively, `149.74,248.1`,and `126.4 ohm^(-1)cm^(2)eq^(-1)`. The value of `wedge_(eq)^(oo)NH_(4)OH` is

A

`(371.44)`

B

`(271.44)`

C

`(71.44)`

D

cannot be predicted from given data

Text Solution

Verified by Experts

The correct Answer is:
B
`wedge_(eq)^(infty) (NH_(4) OH) = wedge_(aq)^(infty) (NH_(4)Cl)- wedge_(eq)^(infty) (NaOH) = 149.74 -126.4 + 248.1 = 271.44Omega^(-1)cm^(2)eq^(-1)`
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