Home
Class 12
CHEMISTRY
wedge(CICH(2))^(infty) COONa =224 ohm ^...

`wedge_(CICH_(2))^(infty) COONa =224 ohm ^(-1) cm^(2) "g equiv"^(-)`
`wedge_(NaCI)^(infty)=38.5 ohm ^(-1) "g equiv"^(-1)`
`wedge_(HCI)^(infty)=203 ohm ^(-1) cm^(2) "g equiv"^(-1)`
what is the value of `wedgeCICH_(2)COOH` ?

A

`288.5Omega^(-1) cm^(2) g equiv ^(-1)`

B

`289.5Oemga^(-1) cm^(2) g equiv^(-1)`

C

` 415.5 Omega^(-1) cm^(2)g equiv^(-1)`

D

`59.5 Omega^(-1) g equiv^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`wedge_(CCH_(2)COOH)^(@)= wedge_(CLCH_(2)CONa)+ wedge_(HCL)^(@)- wedge_(Nacl)^(@)=224 + 320 - 38.5 = 415 .5`
Promotional Banner

Similar Questions

Explore conceptually related problems

wedge_(CICH_(2))^(infty) COONa =224 omega^(-1) cm^(2) "g equiv"^(-) wedge_(NaCI)^(infty)=38.5 omega^(-1) "g equiv"^(-1) wedge_(HCI)^(infty)=203 omega^(infty) =203 omega^(-1) cm^(2) "g equiv"^(-1) what is the value of wedgeCICH_(2)COOH ?

lambda_(ClCH_(2)COONa)=224 "ohm"^(-1) cm^(2) " gm eq"^(-1) , lambda_(NaCl)=38.2 "ohm"^(-1) "cm"^(2) gm eq"^(-1) . lambda_(HCl)=203 "ohm"^(-1) cm^(2) "gm eq"^(-1) . What is the value of lambda_(ClCH_(2)COOH) ?

Equivalent conductance of 1M CH_(3)COOH is 10ohm^(-1) cm^(2) "equiv"^(-1) and that at inifinite dilution is 200 ohm^(-1) cm^(2) "equiv"^(-1) . Hence, % ionisation of CH_(3)COOJ is:

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is: