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During the electrolysis of aqueous zinc ...

During the electrolysis of aqueous zinc nitrate.

A

Zinc plates out at the cathode

B

Zinc plates out at the anode

C

Hydrogen gas,`H_(2)` , is evolved at the cathode

D

Oxygen gas,`O_(2)` , is evolved at the anode

Text Solution

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The correct Answer is:
A, D

Aqueous `Zn(NO_(3))_(2)` :
Cathode : `Zn^(2+) (aq) + 2e^(-) rightarrow Zn(s)` `E_(ZN^(2+)//Zn)=-0.76V`
`2H_(2) O (1)rightarrow H_(2) (g) + 2O H^(-) (aq)` `E_(9H_(2)O //H_(2)) =-0.83V`
`2H_(2) O (1)rightarrow O_(2) (g) + 4H^(+) (aq) + 4e^(-)` `E_(H_(2)O //O_(2))=-1.23V`
`No_(3)^(-) rightarrow X`
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