In an exper iment 0.04F was passed through 400mL of 1 M solution of NaCl. What would be the pH of the solution after electrolysis?

Explanation

Electrolysis of NaCl gives `H_(2)(g)` at cathode and `O_(2)(g)` at anode the electrolyte solution contains NaOH after electrolysis
`therefore` Number of equivalents of NaOH formed = 0.04
`0.04xx1000`
`N=(0.04xx1000)/(400) = 0.1`
`[HO^(-)]= 0.1M thereforepOH= -log [HO^(-) ]1` So PH= 13