Two students use same stock solution of `ZNnSO_(4)` and a solution of `CUSO_(4)` , the emf of one cell is 0.03 V higher than that of other. The concentration of `CuSO_(4)` In the other cell `((2.303RT)/(F)= 0.06)`

Explanation

To solve the problem, we need to determine the concentration of the `CuSO4` solution in the cell with the lower EMF, given that the EMF of one cell is 0.03 V higher than the other. We know the concentration of `CuSO4` in the cell with the higher EMF is 0.5 M, and we are given the relationship involving the Nernst equation.

### Step-by-Step Solution:

1. **Understanding the Nernst Equation**:
The Nernst equation relates the EMF of a cell to the concentrations of the reactants and products:
\[
E = E^\circ - \frac{RT}{nF} \ln Q
...