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The molar conductivities of wedge(NaOAc...

The molar conductivities of `wedge_(NaOAc)^(@)` and `wedge_(HCl)^(@)` at infinite dilution in water at `25^(@)C`are 91.0 and 426.2 S `cm^(2)//mol` respectively. To calculate `wedge_(HOAc)^(@)`, the additional value required is :

A

`wedge_(H_(2)O)^(@)`

B

`wedge_(KCl)^(@)`

C

`wedge_(NaOH)^(@)`

D

`wedge_(NaCl)^(@)`

Text Solution

Verified by Experts

According to Kohlrausch's law:
`Lambda_(CH_3COOH)^(0)=Lambda_(CH_3COONa)^(0)+Lambda_(HCl)^(0)-Lambda_(NaCl)^(0)`
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