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The standard Gibbs energy for the given ...

The standard Gibbs energy for the given cell reaction is `KJmol^(-1)` at 298 K is :
`Zn(s)+CU^(2+) (aq) rightarrow Zn^(2+) (aq) + Cu(s)`
`E^(@)= 2V at 298 K`
(Friday's constant , `F = 96000 C mol^-1`)

A

(-192)

B

(-384)

C

`(192)`

D

384

Text Solution

AI Generated Solution

To find the standard Gibbs energy change (ΔG°) for the given cell reaction at 298 K, we can use the relationship between Gibbs energy and cell potential. The formula is: \[ \Delta G° = -nFE° \] Where: - \( \Delta G° \) = standard Gibbs energy change (in joules per mole) ...
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