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Consider the cell, Zn|Zn^(2+)(aq)(1.0M...

Consider the cell,
`Zn|Zn^(2+)(aq)(1.0M)||Cu^(2+)(aq)(1.0M)|Cu` The standard reduction potentially are 0.350V for
`Cu^(2+)(aq)+2e^(-)rarrCu`
and `-0.763V` for `Zn^(2+)(aq)+2e^(-)rarrZn`
(i) Write down the cell reaction
(ii) Calculate the emf of the cell.
(iii) Is the cell reaction spontaneous or not?

Text Solution

Verified by Experts

(i) The cell reaction is `Zn+Cu^(2+) to Zn^(2+)+Cu`
(ii) `E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)=0.350-(-0.763)=1.113V`
Q both `Zn^(2+)` and `Cu^(2+)` are unit concentration,`E=E^(@)=1.113V`
(iii Q `E_(cell)=1.1113lt0`
`DeltaG-=-nEF lt0`
Therefore, the cell reaction is sponteneous.
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