A solution containing one mole per litre of each `Cu(NO_(3))_(2), AgNO_(3), Hg_(2)(NO_(3))_(2)` is being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are
`Ag^(+)//Ag = +0.80 V, HG_(2)^(2+)//Hg = +0.79 V`
`Cu^(+)//Cu = +0.34 V, Mg^(2+)//Mg = -2.37 V`
With increasing valtage, the sequence of deposition of metals on the cathode will be

Options

A. Ag, Hg, Cu, Mg
B. Mg, Cu, Hg, Ag
C. Ag, Hg, Cu
D. Cu, Hg, Ag

Explanation

The reduction potentials (as given) of the ions are in order :
`Ag^(+)gt Hg_2^(2+)gt Cu^(2+)gtM g^(2+)`
`M g^(2+)(aq)` will not be deposition of the metals will be Ag, Hg, Cu