A cell contains two hydrogen electrode. The negative electrode is in contact with a solution of `10^(-6)` M hydrogen ions. The emf of the cell is 0.118 V at `25^(@)`. Calculate the concentration of hydrogen ions at the positive electrode.

Explanation

To solve the problem, we will use the Nernst equation, which relates the cell potential (emf) to the concentrations of the reactants and products involved in the electrochemical reaction. Here are the steps to find the concentration of hydrogen ions at the positive electrode.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Concentration of hydrogen ions at the negative electrode, \([H^+]_{neg} = 10^{-6} \, M\)
- EMF of the cell, \(E_{cell} = 0.118 \, V\)
- Standard electrode potential for hydrogen electrodes, \(E^{\circ}_{cell} = 0 \, V\) (since both electrodes are hydrogen electrodes).
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