Calculate the equilibrium constant for the reaction : `Fe^(2+)+Ce^(4+)hArr Fe^(3+)+Ce^(3+)` Given, `E_(Ca^(4+)//Ce^(3+))^(@)=1.44V` and `E_(Fe^(3+)//Fe^(2+))^(@)=0.68V`

Calculate the equilibrium constant for the reaction : Fe(s)Cd^(2+)(aq)harrFe^(2+)(aq)+Cd(s) ("Given" E_(cd^(2+)//Cd)^(@)=-0.40 V, E_(Fe^(2+)//Fe)^(@)=-0.44 V)

Calculate the value of equilibrium constant for the reaction : 2Fe^(3+)+2I^(-) to 2Fe^(2+)+I_(2) Given that E_(cell)^(@)=0.235" V "

Calculate the equilibrium constant for the reaction Fe+ CuSO_4 → FeSO_4 + Cu at 25^(@)C Given E_(Fe//Fe^(2+))^0=0.44V, E^0(Cu//Cu^(2+))=-0.337V

Calculate at 25^(@) C , the equilibrium constant for the reaction : 2 Fe^(3+) + Sn^(2+) hArr 2 Fe^(2+) + Sn^(4+) Given that E_((Fe^(3+)|Fe^(2+)))^(Theta) = 0.771 V , E_((Sn^(4+) |Sn^(2+)))^(Theta) = 0.150 V

Calculate DeltaG^(@) for the reaction : Cu^(2+)(aq) +Fe(s) hArr Fe^(2+)(aq) +Cu(s) . Given that E_(Cu^(2+)//Cu)^(@) = 0.34 V , E_(Fe^(+2)//Fe)^(@) =- 0.44 V