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A cell, Ag|Ag^(o+)||Cu^(2+)|Cu , initial...

A cell, `Ag|Ag^(o+)||Cu^(2+)|Cu` , initially contains `1 M Ag^(o+)` and `1M Cu^(2+)` ions. Calculate the change in the cell the potential after the passage of `9.65A` of current for `1h.`

Text Solution

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The niumber of faraday's passed `=(9.65xx60xx60)/(96500)=0.36F`
Afterelectroysis :`[Ag^(+)]=1.36M , [Cu^(2+)]=1-0.36/2=0.82M`
`E_1` (before electroysis)`=E^(@)`
`E_2` (after electrosis)`=E^(@)-0.0592/2log.([Ag^(+)]^(2))/([Cu^(2+)])implies E_1-E_2=0.0592/2log. ((0.36)^(2))=0.01 V`/
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