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The following electrochemical cell has b...

The following electrochemical cell has been set-up,
`Pt(1)|Fe^(3+), Fe^(2+) (a=1)||Ce^(4+), Ce^(3+) (a=1) Pt (2)`
`E^(@) (Fe^(3+) //Fe^(2+))=0.77 V, E^(@) (Ce^(4+)//Ce^(3+))=1.61 V`
If an ammeter is connected between the two platinum electrodes, predict the direction of flow of current. Will the current increase or decrease with time ?

Text Solution

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Since, activities of allthe ions are unity ,`E_(cell)=E_(cell)^(@)`.Also left hand electrode is at lower reduction potential,it act as anode and `E=E^(@)(Ce^(4+),Ce^(3+))-E^(@)(Fe^(3+),Fe^(2+))=0.84` i.e.electones will flow from left to right hand electrode and current from right hand electrode [Pt(2)] to left hand electrode [Pt(1)].Also ,`E=E^(@)-0.0592log. ([Fe^(3+)][Ce^(2+)])/([Fe^(2+)][Ce^(4+)])`
As electrolysis proceds, E will decrease and therefore ,current will also decrease.
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