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If the 0.05 molar solution of M^+ is rep...

If the 0.05 molar solution of `M^+` is replaced by a 0.0025 molar solution, then the magnitude of the cell potential would be :

A

35mV

B

70mV

C

140mV

D

700mV

Text Solution

AI Generated Solution

To solve the problem, we will use the Nernst equation, which relates the cell potential to the concentrations of the reactants and products in an electrochemical cell. ### Step-by-Step Solution: 1. **Identify the Nernst Equation**: The Nernst equation for a concentration cell can be expressed as: \[ E_{cell} = E^0_{cell} - \frac{0.059}{n} \log \left( \frac{[M^+]_2}{[M^+]_1} \right) \] ...
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If the 0.05 molar solution of M^+ is replaced by a 0.0025 Molar M^+ solution. then the magnitude of the cell potential would be :

The concentration of potassium ions inside a biological cell is at least 20 times higher than outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simplel model for a concentration cell involving a metal M is M(s)|M^(o+)(aq,0.05 molar )||M^(o+)(aq,1 molar )|M(s) For the abov electrolytic cell, the magnitude of the cell potential is |E_(cell)|=70mV. If the 0.05 moolar solution of M^(o+) is replaced by a 0.0025 molar M^(o+) solution, then the magnitude of the cell potential would be