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Graph between log x//m and log p is a st...

Graph between `log x//m` and `log p` is a straight line inclined at an angle of `45^@` . When pressure is `0.5 atm` and `1n k = 0.693`, the amount of solute adsorbed per gram of adsorbent will be:

A

`1g//g` adsorbent

B

`1.5g//g` adsorbent

C

`2.5g//g`adsorbent

D

`0.25g//g` adsorbent

Text Solution

Verified by Experts

`x/m=1 diamond^1`
since log k = 0.699, hence k = 5 , slope = 1/n = tan `45^@` = 1
`x/2=5?5 g//g` adsorbent.
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