Home
Class 12
CHEMISTRY
0.27 g of a long chain fatty acid was di...

0.27 g of a long chain fatty acid was dissolved in ` 100 cm^ 3 ` of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. The height of the monolayer is ` 10 ^( -x ) ` m. what is numerical value of `x ` ? [Density of fatty acid ` = 0.9 g cm ^ ( -3) , pi = 3 ` ]

A

`10^4 m`

B

`10^2 m`

C

`10^6 m`

D

`10^8 m`

Text Solution

Verified by Experts

Mass of fatty acid=0.027g, Density =`0.9g//cc`
Volume of fatty acid =0.9
Area of plate =100
Volume of fatty acid= Area of plate `times` height of fatty acid layer
`10^6r`
Promotional Banner

Similar Questions

Explore conceptually related problems

A watch-maker's glass is a

0.27 g of fatty acid is dissolved in 100 ml of solvent, 10 ml such solution is taken & placed over round plate. Distance from the centre of edge of round plate is 10 cm. Now solvent is evaporated & only fatty acid is remained. Density of fatty acid is 0.9g//c . Determine height of fatty acid layer. (pi=3)

2.52 g of oxalic acid dehydrate was dissolved in 100 ml of water, 10 mL of this solution was diluted to 500 mL. The normality of the final solution and the amount of oxalic acid (mg/mL) in the solution are respectively-

Long chain molecules of fatty acids are formed by

The total surface area of a cube of an edge 10 cm is

From a point source a light falls on a spherical glass surface ( mu = 1.5 and radius of curvature = 10 cm ). The distance between point source and glass surface is 50 cm . The position of image is