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For a reversible reaction, A + B ? C + D...

For a reversible reaction, `A + B ? C + D , Delta H = – A` kcal. If energy of activation for the forward reaction is B kcal, the energy of activation for backward reaction in kcal is :

A

`-A+B`

B

`A+B`

C

`A-B`

D

`-A-B`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to understand the relationship between the activation energies of the forward and backward reactions in a reversible reaction, along with the enthalpy change (ΔH) of the reaction. ### Step-by-Step Solution: 1. **Identify the Given Information:** - The reaction is \( A + B \rightleftharpoons C + D \). - The enthalpy change (ΔH) for the reaction is given as \( -A \) kcal, indicating that the reaction is exothermic. - The activation energy for the forward reaction is \( B \) kcal. 2. **Understand the Concept of Activation Energy:** - The activation energy (Ea) for the forward reaction is the energy required to convert reactants (A and B) into products (C and D). - The activation energy for the backward reaction (Ea, backward) is the energy required to convert products (C and D) back into reactants (A and B). 3. **Use the Relationship Between Activation Energies:** - For a reversible reaction, the relationship between the activation energies and the enthalpy change can be expressed as: \[ E_a (\text{backward}) = E_a (\text{forward}) + |\Delta H| \] - Here, \( |\Delta H| \) is the magnitude of the enthalpy change. Since ΔH is given as \( -A \) kcal, we have: \[ |\Delta H| = A \] 4. **Substitute the Values:** - Now, substituting the known values into the equation: \[ E_a (\text{backward}) = B + A \] 5. **Final Answer:** - Therefore, the energy of activation for the backward reaction is: \[ \text{Energy of activation for backward reaction} = A + B \text{ kcal} \] ### Summary: The energy of activation for the backward reaction is \( A + B \) kcal. ---
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