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C(6)H(6) +A overset(AlCl(3))(rarr) C(6)H...

`C_(6)H_(6) +A overset(AlCl_(3))(rarr) C_(6)H_(5)CONH_(2)`
A in the above reaction is :

A

`NH_(2)CONH_(2)`

B

`ClCONH_(2)`

C

`CH_(3)CONH_(2)`

D

` CH_(2)(Cl)CONH_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to identify the compound A that reacts with benzene (C₆H₆) in the presence of aluminum chloride (AlCl₃) to produce an amide (C₆H₅CONH₂). This process is indicative of a Friedel-Crafts acylation reaction. ### Step-by-step Solution: 1. **Identify the Reaction Type**: The reaction involves benzene and a compound A in the presence of AlCl₃. This suggests that we are dealing with a Friedel-Crafts acylation reaction, which typically introduces an acyl group (C=O) into the aromatic ring. **Hint**: Recall that Friedel-Crafts reactions involve the formation of an electrophile that reacts with the aromatic compound. 2. **Determine the Product**: The product of the reaction is C₆H₅CONH₂, which indicates that the acyl group is attached to the benzene ring and is followed by an amine group (NH₂). This suggests that the acyl group must be derived from an amide. **Hint**: Focus on the functional groups present in the product to deduce the structure of compound A. 3. **Identify Compound A**: For the reaction to yield an amide, compound A must be an acyl chloride, specifically an acyl chloride that can provide the amide functional group upon reaction. The most likely candidate is acetyl chloride (CH₃COCl), which can provide the acyl group (C=O) and can react with ammonia (NH₃) to form the amide. **Hint**: Consider common acyl chlorides that could react in this manner. 4. **Write the Reaction**: The reaction can be summarized as follows: \[ C_6H_6 + CH_3COCl \overset{AlCl_3}{\rightarrow} C_6H_5COCl + HCl \] Then, the acyl chloride can react with ammonia (NH₃) to form the amide: \[ C_6H_5COCl + NH_3 \rightarrow C_6H_5CONH_2 + HCl \] **Hint**: Remember that the presence of AlCl₃ is crucial for generating the electrophile from the acyl chloride. 5. **Conclusion**: Therefore, the compound A in the reaction is acetyl chloride (CH₃COCl). **Final Answer**: A is acetyl chloride (CH₃COCl).
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MOTION-AROMATIC COMPOUND-Exercise - 2 (Level-I)
  1. which chloroderivative of benzene among the following would undergo ...

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  2. The product is :

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  3. C(6)H(6) +A overset(AlCl(3))(rarr) C(6)H(5)CONH(2) A in the above re...

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  4. Which of the following is most reactive toward SNAr :

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  5. Major, Product (B) is

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  6. Reaction of SO(3) is faster in :

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  7. The mixture of the following four aromatic compounds on oxidation by s...

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  8. Methyl group attached to benzene can be oxidised to carboxyl group by ...

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  9. Compound A and B respectively are :

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  10. The number of benzylic hydrogen atoms in ethylbenzene is :

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  11. The highest yield of m-product is possible by the electrophilic substi...

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  12. Which of the following can be isolated as the product of this reaction...

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  13. Which of the following is/are produced when a mixture of benzene vapou...

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  14. Which of the following is the least reactive in the case of brominatio...

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  15. Above compound undergoes

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  16. Benzene on reaction with ‘A’ forms which on reaction with ‘B’ fo...

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  17. In a reaction of C(6)H(5)Y the major product (gt60%) is m-isomer, so t...

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  18. Which of the following will undergo sulphonation at fastest rate ?

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  19. Which of the following is most reactive towards sulphonation ?

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  20. When sulphonilic acid (p-H(2)NC(6)H(4)SO(3)H) is treated with excess o...

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