Home
Class 12
CHEMISTRY
The orbital picture of a singlet carbene...

The orbital picture of a singlet carbene `(CH_(2))` can be drawn as

A

B

C

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To draw the orbital picture of singlet carbene (CH₂), we need to follow these steps: ### Step 1: Understand the Structure of Carbene Carbene is a species containing a carbon atom that has only six electrons in its valence shell instead of eight. In the case of singlet carbene, the carbon atom is sp² hybridized and has a lone pair of electrons. ### Step 2: Determine the Hybridization For CH₂: - The carbon atom is bonded to two hydrogen atoms and has one lone pair. - The hybridization of the carbon atom in singlet carbene is sp². This means one s orbital and two p orbitals combine to form three sp² hybrid orbitals. ### Step 3: Draw the Hybrid Orbitals 1. **Draw the sp² Hybrid Orbitals**: - Draw three sp² hybrid orbitals arranged in a trigonal planar geometry around the carbon atom. - Each sp² orbital will contain one electron, and the remaining p orbital will contain the lone pair. 2. **Draw the P Orbital**: - The remaining p orbital (which is unhybridized) will be perpendicular to the plane of the sp² orbitals. ### Step 4: Show the Electrons - In the sp² hybrid orbitals, place one electron in each of the two orbitals that overlap with hydrogen atoms (forming σ bonds). - The third sp² orbital will have the lone pair of electrons. - The unhybridized p orbital will be shown with no electrons (or can be shown with a lone electron if considering reactivity). ### Step 5: Indicate the Spin State - In singlet carbene, the two electrons in the sp² orbitals are paired (one clockwise and one counterclockwise), resulting in a total spin of zero. - This can be indicated by showing the paired electrons in the orbital diagram. ### Final Orbital Picture - You will have a carbon atom at the center with three sp² orbitals (two with one electron each for bonding with H, and one with a lone pair) and one unhybridized p orbital. ### Conclusion The orbital picture of singlet carbene (CH₂) consists of one sp² hybridized orbital with a lone pair and two sp² orbitals each bonded to hydrogen atoms, along with one unhybridized p orbital. ---
Promotional Banner

Topper's Solved these Questions

  • AROMATIC COMPOUND

    MOTION|Exercise Exercise - 2 (Level-II)|29 Videos
  • AROMATIC COMPOUND

    MOTION|Exercise Exercise - 3|17 Videos
  • AROMATIC COMPOUND

    MOTION|Exercise Exercise - 4 | Level-II|16 Videos
  • ALKYI HALIDE

    MOTION|Exercise Exercise - 4 | Level-II|8 Videos
  • ATOMIC STRUCTURE

    MOTION|Exercise EXERCISE-4 (LEVEL-II)|18 Videos

Similar Questions

Explore conceptually related problems

The orbital picture of a triplet carbene can be drawn as

RCH=CH_(2) can be obtained by :

The incorrect statement about carbene (CH_(2)) is :

Find out correct representation of singlet carbene :

Stability of overset(+)CH_(2)-CH=CH_(2) can be explained by:

MOTION-AROMATIC COMPOUND-Exercise - 2 (Level-I)
  1. For the electrophilic substitution reaction involving nitration, which...

    Text Solution

    |

  2. Identify the correct order of reactivity in electro- philic substituti...

    Text Solution

    |

  3. The orbital picture of a singlet carbene (CH(2)) can be drawn as

    Text Solution

    |

  4. The orbital picture of a triplet carbene can be drawn as

    Text Solution

    |

  5. It is believed that chloroform and hydroxide ion react to produce an e...

    Text Solution

    |

  6. CHF(2) Br overset(OH^(-))(rarr) (A) [Intermediate] overset("Trans -2-b...

    Text Solution

    |

  7. Ph-underset(14)overset(O)overset("||")(C)-CHN(2) underset(H(2)O)overse...

    Text Solution

    |

  8. Which of the following will not give carbylamine reaction

    Text Solution

    |

  9. (A) Product (A) will be

    Text Solution

    |

  10. overset(I)overset("|")(PhCHBr) overset(PhC equiv CPh)underset("EtOK")(...

    Text Solution

    |

  11. Complete the following reaction

    Text Solution

    |

  12. Intermediate produced during reimer tiemann’s formlylation will be

    Text Solution

    |

  13. Which of the following compound doesn’t gives Hoffmann’s carbyl amine ...

    Text Solution

    |

  14. CH(3) – NH(2) + CHCl(3) + KOH rarr major product will be :

    Text Solution

    |

  15. What is the product of the following reaction ?

    Text Solution

    |

  16. It involves conversion of a carboxylic acid amide into an amine with a...

    Text Solution

    |

  17. It involves conversion of a carboxylic acid amide into an amine with a...

    Text Solution

    |

  18. The given is mechanism of Beckmann rearrangment. Reagent cannot b...

    Text Solution

    |

  19. The given is mechanism of Beckmann rearrangment. Rate determining...

    Text Solution

    |

  20. The given is mechanism of Beckmann rearrangment. Product (X) i...

    Text Solution

    |