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CHF(2) Br overset(OH^(-))(rarr) (A) [Int...

`CHF_(2) Br overset(OH^(-))(rarr) (A)` [Intermediate] `overset("Trans -2-butene")(rarr) (B)`

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To solve the question regarding the reaction of CHF₂Br with OH⁻ and then with trans-2-butene, we will break down the process step by step. ### Step 1: Reaction of CHF₂Br with OH⁻ The first step involves the reaction of CHF₂Br with a hydroxide ion (OH⁻). The hydroxide ion acts as a base and abstracts a proton (H⁺) from the CHF₂Br molecule. **Chemical Equation:** \[ \text{CHF}_2\text{Br} + \text{OH}^- \rightarrow \text{CF}_2\text{Br}^- + \text{H}_2\text{O} \] ### Step 2: Formation of Carbene After the proton abstraction, we have CF₂Br⁻. The bromine (Br) atom is a good leaving group and will leave, resulting in the formation of a carbene intermediate, specifically a singlet carbene (CF₂). **Chemical Equation:** \[ \text{CF}_2\text{Br}^- \rightarrow \text{CF}_2 + \text{Br}^- \] ### Step 3: Reaction with Trans-2-butene Now, the singlet carbene (CF₂) will react with trans-2-butene. The double bond in trans-2-butene can react with the carbene. The carbene will insert itself into the double bond of trans-2-butene. **Chemical Structure of Trans-2-butene:** \[ \text{CH}_3\text{CH}=\text{CH}\text{CH}_3 \] ### Step 4: Insertion of the Carbene When the carbene (CF₂) inserts into the double bond of trans-2-butene, it will form a new carbon-carbon bond. The stereochemistry of the double bond will remain unchanged because the insertion does not lead to a change in the relative positions of the substituents. **Resulting Product Structure:** The resulting product will have the two fluorine atoms attached to one of the carbon atoms that were involved in the double bond of trans-2-butene. ### Final Product The final product can be represented as follows: \[ \text{CH}_3\text{C}(\text{F}_2)\text{C}(\text{H})\text{CH}_3 \] ### Summary of the Reaction The overall reaction can be summarized as: 1. CHF₂Br reacts with OH⁻ to form CF₂Br⁻. 2. CF₂Br⁻ loses Br⁻ to form the singlet carbene CF₂. 3. CF₂ reacts with trans-2-butene to form the final product.
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MOTION-AROMATIC COMPOUND-Exercise - 2 (Level-I)
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  3. CHF(2) Br overset(OH^(-))(rarr) (A) [Intermediate] overset("Trans -2-b...

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  4. Ph-underset(14)overset(O)overset("||")(C)-CHN(2) underset(H(2)O)overse...

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  5. Which of the following will not give carbylamine reaction

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  6. (A) Product (A) will be

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  7. overset(I)overset("|")(PhCHBr) overset(PhC equiv CPh)underset("EtOK")(...

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  8. Complete the following reaction

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  9. Intermediate produced during reimer tiemann’s formlylation will be

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  10. Which of the following compound doesn’t gives Hoffmann’s carbyl amine ...

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  11. CH(3) – NH(2) + CHCl(3) + KOH rarr major product will be :

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  12. What is the product of the following reaction ?

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  13. It involves conversion of a carboxylic acid amide into an amine with a...

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  14. It involves conversion of a carboxylic acid amide into an amine with a...

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  15. The given is mechanism of Beckmann rearrangment. Reagent cannot b...

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  16. The given is mechanism of Beckmann rearrangment. Rate determining...

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  17. The given is mechanism of Beckmann rearrangment. Product (X) i...

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  19. Product (A) will be

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  20. Give the major organic product of the following re- action :

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