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Which of most reactive towards nucleophi...

Which of most reactive towards nucleophilic aromatic substitution.

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To determine which compound is most reactive towards nucleophilic aromatic substitution, we need to analyze the effect of substituents on the aromatic ring and how they influence the electron density. Here’s a step-by-step solution: ### Step 1: Understand Nucleophilic Aromatic Substitution Nucleophilic aromatic substitution involves the addition of a nucleophile to an aromatic ring, followed by the departure of a leaving group. The reactivity of the aromatic compound depends on the electron density of the ring and the nature of the substituents. **Hint:** Remember that nucleophiles are electron-rich species and will attack areas of low electron density on the aromatic ring. ### Step 2: Identify the Substituents Let’s consider the four options provided. Typically, these options will include different substituents such as halogens (like fluorine, chlorine), alkyl groups (like methyl), and electron-withdrawing groups (like nitro). **Hint:** Focus on how each substituent affects the electron density of the aromatic ring. ### Step 3: Analyze Electron-Withdrawing and Electron-Donating Effects - **Electron-Withdrawing Groups (EWGs)** like nitro (-NO2) decrease the electron density on the aromatic ring, making it more susceptible to nucleophilic attack. - **Electron-Donating Groups (EDGs)** like alkyl groups (e.g., -CH3) increase the electron density, making the ring less reactive towards nucleophiles. **Hint:** Identify which substituents are EWGs and which are EDGs in your options. ### Step 4: Determine the Most Reactive Compound 1. **For a compound with a halogen (like fluorine):** The bond between carbon and fluorine is highly polar due to fluorine's high electronegativity, making it a good leaving group. However, the presence of electron-donating groups can reduce reactivity. 2. **For compounds with nitro groups:** The nitro group is a strong electron-withdrawing group, which significantly decreases electron density on the ring, enhancing reactivity towards nucleophiles. **Hint:** Compare the electron density of the aromatic rings in each option to see which one is most affected by EWGs. ### Step 5: Conclusion After analyzing the effects of substituents: - The compound with the nitro group (-NO2) will be more reactive towards nucleophilic aromatic substitution compared to those with electron-donating groups or less polar leaving groups. - Among the options, the compound with the nitro group and a good leaving group (like iodine) will be the most reactive. **Final Answer:** The compound with the nitro group is the most reactive towards nucleophilic aromatic substitution.
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MOTION-AROMATIC COMPOUND-Exercise - 2 (Level-II)
  1. Which of the following structures correspond to the product expected, ...

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  2. Conjugation of electron withdrawing groups, e.g., -CHO, -overset(O)ove...

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  3. Which of most reactive towards nucleophilic aromatic substitution.

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  4. Nitro benzene reacts with Me-overset(O)overset("||")(C)-Cl in presence...

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  5. Which of the following is ortho-para directing group

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  6. The structure of the compound that gives a tribromo derivative on trea...

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  7. Amongst the following, moderately activating groups is

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  8. Which of the following is ortho para directing

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  9. Of the species PhSH, Ph underset(O)underset("||")(S)R, ph underset(O)u...

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  10. Which of the following group(s) activate the benzene ring towards elec...

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  11. Statement-1 : Rate of nitration is C(6)H(6) cong C(6) D(6) cong C(6)T(...

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  12. Product (A) will be

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  13. Product (A) is

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  14. Which aromatic compound is obtained when noctane undergoes catalytic h...

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  15. Benzoic acid may be prepared by the oxidation of:

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  16. Isopropylbenzene can be prepared by :

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  17. In which of the following reaction t-butylbenzene is formed:

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  18. Product is

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  19. Which of the following reactions of bezene proves the presence of thre...

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  20. Electrophile NO(2)^(o+) attacks the following in which cases NO(2)^(o...

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