`CH_(3) - overset(O)overset(||)(C ) - CH_(3) + H - overset(O)overset(||)(C ) - H " "overset(KOH)(rarr)`
(A) major. Product (A) is :

Options

A.
B.
C.
D.

Answer

To solve the given reaction, we need to analyze the components and the reaction conditions. The reaction involves a ketone (acetone) and formaldehyde in the presence of a strong base (KOH).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are acetone (CH₃COCH₃) and formaldehyde (HCHO).
- The presence of KOH indicates that we are dealing with a base-catalyzed reaction.

2. **Understand the Role of KOH**:
- KOH is a strong base that will deprotonate the α-hydrogen of acetone.
- This results in the formation of an enolate ion from acetone.

3. **Formation of the Enolate Ion**:
- The α-hydrogen of acetone (the hydrogen attached to the carbon adjacent to the carbonyl group) is acidic and can be removed by OH⁻.
- The resulting enolate ion has a negative charge on the carbon adjacent to the carbonyl group.

4. **Nucleophilic Attack**:
- The enolate ion acts as a nucleophile and attacks the carbonyl carbon of formaldehyde.
- This step forms a tetrahedral intermediate.

5. **Proton Transfer**:
- After the nucleophilic attack, the tetrahedral intermediate collapses, leading to the formation of a new carbon-carbon bond.
- The hydroxyl group (OH) from the intermediate can be protonated to form water (H₂O).

6. **Final Product Formation**:
- The final product of this reaction is a β-hydroxy ketone.
- The structure of the product will be: CH₃C(OH)(CH₂CHO)CH₃, which can be simplified to a compound with a hydroxyl group and a carbonyl group.

7. **Conclusion**:
- The major product (A) of the reaction is a β-hydroxy ketone formed from the condensation of acetone and formaldehyde.

### Final Answer:
The major product (A) is: **CH₃C(OH)(CH₂CHO)CH₃** (β-hydroxy ketone).