A gas 'X' is present with saturated water vapour over water liquid at total pressure of 1.5 atm. Vapour pressure of `H_2O` at same temperature is 0.5 atm. What is the solubility of gas 'X' in terms of moles in 10 moles `H_2O`. The slope of the graph is 5000.

Explanation

`P_T=P_x+P_(H_2O)`
`P_x=1.5-0.5=1atm`
slope of graph `=K_H=5xx10^3`
`P_x=K_H(n_x)/n_(H_2O)`
`1=5xx10^3xxn_x/10`
`n_x=1/500=2xx10^(-3)`