To `500 cm^(3)` of water, `3 xx 10^(-3) kg` of acetic acid is added. If `23%` of axcetic acid is dissociated wha will be the depression in freezing point? `K_(f)` and density of water are `1.86 K kg^(-1) mol^(-1)` and `0.997 g cm^(-3)` respectively.

Explanation

`"Molarity of acidic acid"=(3xx10^(-3)xx10^3xx1000)/(60xx0.997xx500)`
=0.1003
Total number of moles per kg of solvent
= 0.1003 (1 + 0.23)
`DeltaT_"f"=K_"f"m=1.86xx0.1003xx1.23=0.23^@C`