The density of a solution containing `13%` by mass of sulphuric acid is `1.09g//mL`. Calculate the molarity and normality of the solution

Options

A. 1.445 M
B. 14.45 M
C. 144.5 M
D. 0.1445 M

Answer

A

Explanation

Volume of 100 gram of the solution = `100/d`
`100/1.09mL=100/(1.09xx1000)litre`
`1/(1.09xx10)litre`
Number of moles of `H_2SO_4` in 100 gram of the solution =`11/98`
`"Molarity"=("No. of moles of "H_2SO_4)/("Volume of solution in litre ")`
`13/98xx(1.09xx10)/1=1.445M`