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Calculate the quantity of sodium carbona...

Calculate the quantity of sodium carbonate (anhydrous) required to prepare 250mL `(M)/(10)` solution.

A

2.65 gram

B

4.95 gram

C

6.25 gram

D

None

Text Solution

Verified by Experts

The correct Answer is:
A

We know that
`"Molarity"=W/(MxxV)`
where:
W = Mass of `Na_2CO_3` in gram
M = Molecular mass of `Na_2CO_3` in grams = 106
V = Volume of solution in litres = `250/1000=0.25`
`"Molarity"=1/10`
Hence, `=1/10=W/(106xx0.25`
or W `=(106xx0.25)/10=2.65 grams`
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