A solution has ` 25% `of water,` 25% `ethanol and ` 50% `acetic acid by mass. Calculate the mol e fraction of each component.

Options

A. 0.50, 0.3, 0.19
B. 0.19, 0.3, 0.50
C. 0.3, 0.19, 0.50
D. 0.50, 0.19, 0.3

Answer

D

Explanation

Since 18 g of water = 1 mole
25 g of water = `25/18` = 1.38 mole
Similarly, 46 g of ethanol = 1 mole
25 g of ethanol = `25/46` = 0.55 moles
Again, 60 g of acetic acid = 1 mole
50 g of acetic acid = `50/60` = 0.83 mole
`:.` Mole fraction of water
`1.38/(1.38+0.55+0.83)=0.50`
Similarly, Mole fraction of ethanol
`0.55/(1.38+0.55+0.83)=0.19`
Mole fraction of acetic acid
`0.83/(1.38+0.55+0.83)=0.3`