Calculate normality of the mixure obtained by mixing `100ml` of `0.1N HCL` and `50 ml` of `0.25N NaOH` solution

Options

A. 0.0467 N
B. 0.0367 N
C. 0.0267 N
D. 0.0167 N

Answer

D

Explanation

Meq. of HCl =100 `xx` 0.1 = 10
Meq. of NaOH = 50 `xx` 0.25 = 12.5
HCl and NaOH neutralize each other with equal eq
Meq. of NaOH left = 12.5 – 10 = 2.5
Volume of new solution = 100 + 50 = 150 ml.
`N_(NaOHO) " left"=2.5/150=0.0167N`
Hence normality of the mixture obtained is 0.0167 N