How many kilograms of wet `NaOH` containing `12%` water are required to prepare 60 litre of 0.50 N solution ?

Options

A. 1.36 kg
B. 1.50 kg
C. 2.40 gm
D. 3.16 kg

Answer

A

Explanation

One litre of 0.50 N NaOH contains = 0.50 × 40g = 20g = 0.020 kg
`:.` 60 litres of 0.50 N NaOH contain
= 0.020 × 60 kg = 1.20 kg NaOH
Since the given NaOH contains 12% water, the amount of pure NaOH in 100 kg of the given NaOH
= 100 – 12 = 88 kg
Thus 88 kg of pure NaOH is present in 100 kg wet NaOH
`:.`1.20 kg of pure NaOH is present in
`100/88xx120=`1.36 kg wet NaOH