A solution is prepared by dissolving 5.64g of flucose in 60g of water. Calculate the following :
(i) mass percent of each of glucose and water
(ii) molality of the solution
(iii) mole fraction of each of glucose and water.

Explanation

(i) Total mass of solution
= 5.64 + 60 = 65.64 g
Mass percent of glucose `=5.64/65.64xx100=8.59%`
Mass percent of water
= (100 – Mass percent of glucose)
= (100 – 8.59) = 91.41%
No. of moles of glucose `=5.64/180`
Mass of water in kg `=60/1000`
Molarity `=5.64/180xx1000/60=0.522m`
No. of moles of glucose `=5.64/180=0.0313`
No. of moles of water `=60/18=3.333`
Mole fraction of glucose
`0.0313/(3.333+0.0313)=0.0093`
Mole fraction of water `=3.333/(3.333+0.0313)=0.9907`