Two solution of `H_(2)SO_(4)` of molarities x and y are mixed in the ratio of `V_(1) mL : V_(2) mL` to form a solution of molarity `M_(1)`. If they are mixed in the ratio of `V_(2) mL : V_(1) mL`, they form a solution of molarity `M_(2)`. Given `V_(1)//V_(2) = (x)/(y) gt 1 and (M_(1))/(M_(2)) = (5)/(4)`, then `x : y` is

Options

A. `2:1`
B. `4:1`
C. `1:2`
D. `3:1`

Explanation

Molarity of the mixture can be calculated as.
`M_1V_1+M_2V_2=M_R(V_1+V_2)`
where, `M_R` = resultant solution
`V_1xxx+V_2xxy=M_1(V_1+V_2)`
`V_2xxx+V_1xxy=M_2(V_1+V_2)`
Dividing equation (i) by equation (ii), we get
`(V_1x+V_2y)/(V_2x+V_1y)=M_1/M_2`
`=X/y"we can calculate "x:y`.