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Lowering of vapour pressure due to a sol...

Lowering of vapour pressure due to a solute in `1` molal aqueous solution at `100^(@)C` is
a.`13.44 mm Hg` ,b. `14.14 mm Hg` ,c.`13.2 mm Hg` ,d. `35.2 mm Hg`

A

13.44 mm Hg

B

14.12 mm Hg

C

31.2 mm Hg

D

35.2 mm Hg

Text Solution

Verified by Experts

The correct Answer is:
A
Molality and mole fraction are related as follows :
`m=(x_Bxx1000)/((1-x_B)xxm_A)" "m=1`
`m=(x_Bxx1000)/((1-x_B)xx18)" "x_B="mole fraction of solute"`
`m_A` = molar mass os solvent
`x_B=0.0176,x_A=0.9824`
`p=p_0x_A`
`p=760xx0.9824=746.624`
`Deltap=p_0-p=760-746.624=13.4` mm Hg.
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